- A man in India was nabbed for trying to smuggle 100 iPhone X
- Reports said the 53-year-old man was travelling from Dubai
- The total cost of the smuggled units is Indian Rupees 85 lakh
A 53-year-old man was apprehended after he reportedly tried to smuggle 100 units of the pricey iPhone X at an airport in India last Friday.
As per India Today, the man was travelling from Dubai and was caught by the Customs department trying to bring in 100 iPhone X which costs at least $1,000 per unit.
Apple’s flagship phone is currently the most expensive iPhone model in India with the base model (64GB) costing around 95,000 Indian Rupees while its high-end variant (256GB) has a price tag of around 1,08,000 Indian Rupees including custom duty.
“The accused was coming from Dubai in flight no – 6E048. He was apprehended when he was coming out through the green channel,” India Today quoted a source as saying.
“A detailed search led to the seizure of the mobile phones worth around Rs 85 lakh from his possession,” the source added.
The man is being currently being investigated, the report said.
CEO Tim Cook has recently disclosed that iPhone X is the world’s best-selling phone during the first quarter of this year; selling more than 16 million units across the world for the first three months of 2018 for a 5% market share.
The next three places were also taken by previous iPhone models – iPhone 8 (12.5-M), iPhone 8 Plus (8.3-M) and iPhone 7 (5.6-M).
On the other hand, Xiaomi’s Redmi 5A and Samsung’s S9 Plus were the best-selling Android models in the world for the same period.